n=(n^2-3n)/14

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Solution for n=(n^2-3n)/14 equation: 


n in (-oo:+oo)

n = (n^2-(3*n))/14 // - (n^2-(3*n))/14

n-((n^2-(3*n))/14) = 0

n-((n^2-3*n)/14) = 0

(-1*(n^2-3*n))/14+n = 0

(-1*(n^2-3*n))/14+(14*n)/14 = 0

14*n-1*(n^2-3*n) = 0

17*n-n^2 = 0

17*n-n^2 = 0

n*(17-n) = 0

17-n = 0 // - 17

-n = -17 // * -1

n = 17

n*(n-17) = 0

(n*(n-17))/14 = 0

(n*(n-17))/14 = 0 // * 14

n*(n-17) = 0

( n-17 )

n-17 = 0 // + 17

n = 17

( n )

n = 0

n in { 17, 0 }

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